Find speed of object traveling up a ramp

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To find the speed of an object at the bottom of a ramp, conservation of energy principles are applied. The object reaches a height of 40.0 m at point B, converting its initial kinetic energy into potential energy. The gravitational acceleration is given as 10.0 m/s², and the ramp's angle is 30.0 degrees. The calculations involve determining the potential energy at the top and equating it to the kinetic energy at the bottom. The final speed at point A can be derived from these energy equations.
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Homework Statement



An object approaches the bottom of a ramp, point A. It goes up the ramp and turns around at point B, which is 40.0 m above A. The ramp makes an angle of 30.0 degrees with the horizontal. What is the speed of the object at point A? Neglect friction.

Homework Equations



g=10.0 m/s (squared)


The Attempt at a Solution



I did 2cos(30)40
 
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I would use conservation of energy - assuming you read the question to say it has stopped at point B.
Write the kinetic energy of the object at the start of the ramp
At the top of the ramp all this ke is pe, write down the equation for PE.
 

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