Find the aceleration of the disk when falling (rotation)

AI Thread Summary
The discussion revolves around calculating the acceleration of a disk with a mass M and radius R, which is hanging by a rope with an additional mass m attached. Participants suggest treating the disk and the hanging mass as a single system to simplify the analysis. The key equations involve torque and Newton's laws, with a focus on the forces acting on the combined mass. A shortcut method is proposed for calculating acceleration, incorporating both the gravitational force and the effective mass due to rotation. The conversation emphasizes understanding the dynamics of the system for accurate results.
Hernaner28
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Homework Statement


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I have that system and the problem says:

A disk of mass M and radious R are posed are shown. The disk is hanging by an ideal rope which is coiled up. From a smooth axis through the center of the disk is haning a body m. Calclate the module of the aceleration of the center of mass of the disk.

Homework Equations





The Attempt at a Solution



I've done this excercise but without the small mass hanging there. What I did was to use the torque and Newton formulas, that simple. But here I've got two bodies and tensions are driving me crazy. Should I consider the bodies as a single one?

Thanks!
 

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Hi Hernaner28! :smile:
Hernaner28 said:
I've done this excercise but without the small mass hanging there. What I did was to use the torque and Newton formulas, that simple. But here I've got two bodies and tensions are driving me crazy. Should I consider the bodies as a single one?

Yes, since they're moving together, you can regard them as a single body …

add the m to the mass of the pulley, but not to its moment of inertia. :wink:
 
Done! Thank you!

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yes! :smile:

here's a shortcut (i don't know whether your professor would approve of this, but it's certainly a good way of checking the answer) …

the force is (M+m)g, and the effective mass is the actual mass M+m plus the "rolling mass" I/r2 = M/2,

so a = (M + m)/(3M/2 + m) :wink:
 
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