Find the Arc Length of a Curved Line

zacman2400
Messages
9
Reaction score
0

Homework Statement



find the arc length
x=2e^t, y=e^-t, z=2t

Homework Equations





The Attempt at a Solution


dr/dt=2e^ti-e^-tj+2
ds/dt=sqrt((4e^2t)+(e^-2t)+4)) dt
=integral from 0 to 1 sqrt(4e^4t+4e^2t+1)/e^t
sorry about the lack of latex, I have no idea how to integrate this function
 
Physics news on Phys.org
you have got it right.
why not try splitting them out. Take out the power and apply linearity rule to each integrand?
 
zacman2400 said:

Homework Statement



find the arc length
x=2e^t, y=e^-t, z=2t

Homework Equations





The Attempt at a Solution

If you don't know LaTeX, at least use some spaces to make what you have written more readable.
zacman2400 said:
dr/dt=2e^ti-e^-tj+2
Don't you mean
dr/dt = 2e^t i - e^(-t) j + 2k?
zacman2400 said:
ds/dt=sqrt((4e^2t)+(e^-2t)+4)) dt
Are you sure about the middle term in the radical above?
zacman2400 said:
=integral from 0 to 1 sqrt(4e^4t+4e^2t+1)/e^t
Shouldn't your integrand be ds/dt * dt?
zacman2400 said:
sorry about the lack of latex, I have no idea how to integrate this function
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...
Back
Top