Find the centripetal acceleration of the moon

AI Thread Summary
The discussion revolves around calculating the centripetal acceleration of the moon, which orbits the Earth at a distance of approximately 250,000 miles with a period of 27.3 days. Participants clarify that the distance given is the radius of the moon's orbit, not the circumference. The correct formula for centripetal acceleration is ac = v²/r, where v must be the linear velocity in meters per second, not angular velocity. There is confusion regarding the conversion of units and the application of formulas, with emphasis on calculating the velocity by finding the circumference of the orbit and dividing it by the total time in seconds. Ultimately, the conversation highlights the importance of accurate unit conversion and understanding the distinction between radius and circumference in orbital mechanics.
BrainMan
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Homework Statement


The moon circles the Earth with a period of 27.3 days at a distance of about 250000 mi. Find the centripetal acceleration of the moon.

Homework Equations


ac = v2/r

The Attempt at a Solution


I first found the velocity by converting 2 pi radians per 27.3 days to radians per second.
2 pi / 27.3/ 24/ 60/60 = 2.66 x 10-6 radians per second.
Then I converted miles to meters to find the radius.
250000 x 1609.34 / 2 pi = 631986340.1
Then I plugged these numbers into the above equation to find the acceleration and got 1.12 x 10-20 rad/s. The correct answer is 2.85 x 10-3 rad/s
 
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Seems like you're confusing the angular velocity with the velocity. Also 250000miles is the radius already. No need to divide by 2 pi. Finally, you made some other mistake. I can't tell what it is since you didn't post your calculation. Don't just describe your calculation. Post it.
 
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dauto said:
Seems like you're confusing the angular velocity with the velocity. Also 250000miles is the radius already. No need to divide by 2 pi. Finally, you made some other mistake. I can't tell what it is since you didn't post your calculation. Don't just describe your calculation. Post it.

Sorry (2.66 x 10-6)2/631986340.1 = 1.12 x 10-20
 
In your formula ac = v2/r, v is the velocity in meters/second, not the angular velocity in radians/second.

There is a different formula for the acceleration that uses angular velocity and radius, if you want to do it that way.
 
AlephZero said:
In your formula ac = v2/r, v is the velocity in meters/second, not the angular velocity in radians/second.

There is a different formula for the acceleration that uses angular velocity and radius, if you want to do it that way.
OK I see. Is the 250000 mi the radius or the circumference?
 
BrainMan said:
OK I see. Is the 250000 mi the radius or the circumference?

That's the distance between the moon and the earth. Draw a picture of the orbit, and remember that the Earth barely moves at all.
 
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BrainMan said:
at a distance of about 250000 mi.

dauto said:
250000miles is the radius already.
If it is 250000 mi above the Earth, it should not be the radius. Thou should also include the Radius of the Earth. Am I wrong?
 
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dauto said:
That's the distance between the moon and the earth. Draw a picture of the orbit, and remember that the Earth barely moves at all.

I understand that. How do I find the velocity in m/s?
 
BrainMan said:
I understand that. How do I find the velocity in m/s?

Find the circumference of the orbit (in meters) and divide it by however many seconds are in 27.3 days
 
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Nathanael said:
Find the circumference of the orbit (in meters) and divide it by however many seconds are in 27.3 days

OK I got it right! Thanks!
 
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adjacent said:
If it is 250000 mi above the Earth, it should not be the radius. Thou should also include the Radius of the Earth. Am I wrong?

That's negligible specially considering that the moon's orbit really isn't circular. We're going for a ball park calculation here.
 
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