Find the Charge Needed for a 1.20V Voltage at 5.0m

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To achieve a voltage of 1.20 V at a distance of 5.0 m from a charged sphere, the correct equation to use is V = kQ/r, where k is a constant and r is the distance. The charge Q can be calculated by rearranging the equation to solve for Q once the values for V and r are known. The resulting charge will be in Coulombs, which can be converted to nanoCoulombs by multiplying by 10^-9. It is essential to understand and properly use SI units for accurate calculations. This discussion emphasizes the importance of using the correct formula and unit conversions in electrostatics.
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We wish to place a small charged sphere at a distance of 5.0 m from a point in space such that the voltage at that point is 1.20 V. How much charge should be on the sphere (in nC)?
 
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What have you tried? What equations do you think you might need?
 
I've tried V = kQ/r and V = kQ/r^2. If either of those are right, please respond, and if one of them is, then I feel I'm having conversion errors.
 
r is essentially the distance (my teacher has been using 'radius' all this time)
 
That second equation you're using with the r^2, don't use that one. The one you want to use is the first one. k is a constant and r is the radial distance (the question specifies that as 5.0m). If the voltage at that point is 1.20V, and you know the value of k and r, then just solve for Q.
 
The answer comes out in Coulombs, right? How would I convert that to nanoCoulombs? Just multiply by 10^-9?
 
Yea, in coulombs.

u know 1 [nC] = 1E-9 [C]
say you get x coloumb
x [C] * 10^-9 [?]/1[?] ??
you must learn to use those SI units
 
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