Find the critical rotation rate

  • Thread starter Thread starter Milotoadfoot
  • Start date Start date
  • Tags Tags
    Rate Rotation
AI Thread Summary
The discussion revolves around calculating the critical rotation rate of a clothes dryer drum, with a radius of 0.30 m, where clothes experience weightlessness. Participants emphasize that weightlessness occurs when the net acceleration equals zero, which requires balancing gravitational force with centripetal acceleration. The critical angular velocity can be derived from the relationship between linear velocity and angular velocity, using the equation arad = v²/R. The apparent gravity experienced by the clothes at the bottom of the drum is also a key point, needing expression in multiples of g. Understanding these concepts is essential for solving the problem accurately.
Milotoadfoot
Messages
4
Reaction score
0

Homework Statement



The tumbler in an upright clothes dryer rotates at a critical angular
velocity so that clothes passing over the top briefly experience weightlessness.
If the radius of the drum is 0.30 m, what is this critical rotation rate? (Express
your answer in both radians per second and revolutions per min (RPM).) At
this rate, what is the apparent gravity felt by the clothes when they pass over
the bottom? (Express your answer in multiples of g.)

Homework Equations



arad=v2/R

The Attempt at a Solution


I don't see how we can extrapolate a critical rotation rate from the given equation. Maybe I am just missing something or are we looking for Vf?
 
Last edited:
Physics news on Phys.org
Consider what the term "weightlessness" means and implies with regards to net acceleration.
 
You'll need the angular velocity for the answer, but you can start with the velocity if you like.
There is no need to extrapolate anything. When do you get weightlessness?
 
You get weightlessness when g=0
 
Milotoadfoot said:
You get weightlessness when g=0

But g is not zero. It's a constant 9.8 m/s2. What other acceleration is in play? What's the net acceleration?
 
Well we care about the acceleration of ω right?
 
ω is constant, there is no "acceleration of ω". There is an acceleration that has a relation to ω, yes.
 
Perhaps "weight" can be thought of as normal force exerted on the body.
 

Similar threads

Back
Top