Find the current and potential difference

[spice1510]

Homework Statement

For the circuit shown in the figure, find the current through and the potential difference across each resistor.
http://session.masteringphysics.com/problemAsset/1169464/1/jfk.Figure.23.P60.jpg

Homework Equations

V=I(amps)/R(ohms) and Req=R1+R2+R3...

The Attempt at a Solution

Rearranging the circuit:
R(8ohm) and R(24ohm) are parallel so (1/8+1/24)^-1=6ohm
that created a series of R(6ohm)+R(6ohm) so R6+R6=R(12ohm)
now I have the first circuit R(4ohm) in parallel with R(12ohm) and R(24ohm)
(1/4+1/12+1/24)^-1=2.67ohm for equivalent resistance for the entire circuit

24V=I*2.67ohm
I=9Amps

across the 4ohm resistor the current is? I=9A because the current is the same or is it 9A divided across the 3 parallel resistors?

I'm either getting it wrong because I put the 4ohm by itself (before the junction correct?) or if it's in series with the 2 6ohm resistors then that's my error but I've definitely tried it 4 different ways and am getting something wrong.

 

[SammyS]

Homework Statement

For the circuit shown in the figure, find the current through and the potential difference across each resistor.
http://session.masteringphysics.com/problemAsset/1169464/1/jfk.Figure.23.P60.jpg

Homework Equations

V=I(amps)/R(ohms) and Req=R1+R2+R3...

The Attempt at a Solution

Rearranging the circuit:
R(8ohm) and R(24ohm) are parallel so (1/8+1/24)^-1=6ohm
that created a series of R(6ohm)+R(6ohm) so R6+R6=R(12ohm)
now I have the first circuit R(4ohm) in parallel with R(12ohm) and R(24ohm)

No, the 12Ω and 24Ω are in parallel. The 4V is in series with the (12V & 24V) combination.

(1/4+1/12+1/24)^-1=2.67ohm for equivalent resistance for the entire circuit

24V=I*2.67ohm
I=9Amps

across the 4ohm resistor the current is? I=9A because the current is the same or is it 9A divided across the 3 parallel resistors?

I'm either getting it wrong because I put the 4ohm by itself (before the junction correct?) or if it's in series with the 2 6ohm resistors then that's my error but I've definitely tried it 4 different ways and am getting something wrong.

Homework Statement

Homework Equations

The Attempt at a Solution

See the comment in red.

 

[spice1510]

so 4ohm in series with (1/12+1/24)^-1 which equals 8ohm

4ohm+8ohm (series)=12ohm for the entire circuit

24V=12ohm*I
I=2amps

 

[SammyS]

so 4ohm in series with (1/12+1/24)^-1 which equals 8ohm

4ohm+8ohm (series)=12ohm for the entire circuit

24V=12ohm*I
I=2amps

Yes.

Now, work your way back through all the resistors.