Find the diameter of the piston at certain heights

AI Thread Summary
The discussion focuses on solving for the diameter of a piston at different heights using the equations related to force and area. The user successfully solved part A but encountered issues with part B, specifically obtaining an undefined value for r2. Participants emphasize the importance of showing calculations and ensuring consistent units throughout the equations. There is also a suggestion to clarify how certain terms were derived, particularly regarding the manipulation of the equation. The conversation highlights the need for careful unit management and verification of calculations to resolve the problem effectively.
sgk777
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Homework Statement
A 56.0 kg cheerleader uses an oil-filled hydraulic lift to hold four 130 kg football players at a height of 0.900 m. The diameter of the cheerleader's piston is 18.0 cm.

A) What is the diameter of the football players' piston if the cheerleader and football players are at the same height?

B) What is the diameter of the football players' piston if the football players are held to a height 0.900 m above the cheerleader?
Relevant Equations
F1/A1 = F2/A2 + pgh
1698536610892.png

I solved for part A by using the equation r2 = sqrt(m2/m1) * r1

im having trouble solving for part B, I know that you would use the equation F1/A1 = F2/A2 + pgh and solve for r2, but when I solved for r2, I got an undefined number. Can someone run me through this question?
 
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Welcome, @sgk777 !

We need you to post your calculations, please.
 
Lnewqban said:
Welcome, @sgk777 !

We need you to post your calculations, please.
A)

1698538424520.png


B)

F1/A1 = F2/A2 + pgh
(F1/A1 = F2/A2 + pgh)(A1 * A2) multiply both sides by A1 and A2 to cancel out the denominator
that gives:
A2F1 = A1F2 +A1A2(pgh)
subtract A1A2(pgh) from both sides:
A2F1 - A1A2(pgh) = A1F2
factor out A2:
A2(F1 - A1(pgh)) = A1F2
divide both sides by (F1 - A1(pgh)):
A2 = A1F2 / (F1 - A1(pgh))
solve for r2, where A1 = pi(r1)^2 and A2 = pi(r2)^2 and F1 = m1g and F2 = m2g.
that gave me:
1698538729776.png

when i plugged in the known values, i got an undefined number.
 
redoing my calculations, i got this:

1698539414334.png

it doesnt seem reasonable though
 
It might be useful to write down the units. Try again, please.
 
1698540728097.png
 
  1. What units on 900 are required so that the equation makes sense?
  2. Where did you get that number?
  3. Are you using /mixing cm and m in tha same equation? Care is required.
 
sgk777 said:
A2 = A1F2 / (F1 - A1(pgh))
solve for r2, where A1 = pi(r1)^2 and A2 = pi(r2)^2 and F1 = m1g and F2 = m2g.
that gave me:
View attachment 334444
How did ##F1 - A1(pgh)## become ##1-A1(pgh)##? (I assume p is 900 kgm-3.)
 
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