Find the distance traveled by the block

AI Thread Summary
The problem involves a block of mass 5 kg on a smooth incline of 73.74 degrees, with gravity set at 9.8 m/s². The key equations used are mgsinX for the force down the plane and mgcosX for the force perpendicular to the incline. The acceleration calculated is 9.4 m/s², leading to the distance traveled by the block in 0.8 seconds being computed using the equation s = ut + 1/2At². The final result for the distance traveled is 3.008 meters, which is confirmed as correct. The discussion emphasizes the application of basic physics principles to solve the problem.
DeanBH
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Homework Statement


A smooth plane is inclined at 73.74 Degrees to the horizontal a block of mass 5kg is on the slope.

its 73.47 degrees inclined
5kg mass
g = 9.8

Find the distance traveled by the block in 0.8 Seconds



The Attempt at a Solution



i can't quite remember how i find this out.

mgsinX works down the plane
mgcosX works in the direction of graity

its smooth = no friction. i can't remember how i balance the equation to work out acceleration and things that i can put it into an equation of motion to find time
 
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DeanBH said:

Homework Statement


A smooth plane is inclined at 73.74 Degrees to the horizontal a block of mass 5kg is on the slope.

its 73.47 degrees inclined
5kg mass
g = 9.8

Find the distance traveled by the block in 0.8 Seconds



The Attempt at a Solution



i can't quite remember how i find this out.

mgsinX works down the plane
mgcosX works in the direction of graity

its smooth = no friction. i can't remember how i balance the equation to work out acceleration and things that i can put it into an equation of motion to find time


gSinX = A = 9.4

s = ut + 1/2AT^"

s = 0*0.8 + 1/2 * 9.4 * 0.8^2

= 3.008 metres..

right? =)
 
I don't see any errors, good work!
 

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