Find the drift speed of electrons in a wire

AI Thread Summary
To find the drift speed of electrons in a copper wire carrying a current of 8 amps, the relevant variables include the charge of an electron (1.6 x 10^-19 coulombs) and the cross-sectional area calculated using the wire's radius (1.2 x 10^-3 m). The free electron density is derived from the density of copper (8.92 g/cm^3), yielding approximately 8.45 x 10^22 electrons/cm^3. The formula used for drift speed is v_d = I/(neA), but the initial calculation of 130.8 m/s was incorrect due to unit mismatches. Ensuring consistent unit conversion is crucial for accurate results.
Jaccobtw
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Homework Statement
A cylindrical copper wire has a radius of 1.2∗10^−3 m. It carries a constant current of 8.00A. What is the drift speed of the electrons in the wire in m/s? Assume each copper atom contributes one free electron to the current. The density of copper is 8.92g/cm^3.
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Relevant Equations
$$v_d = \frac{I}{neA}$$
We need to find each variable. ##I## is already given to us as 8 amps. The charge of an electron is 1.6 x 10^-19 coulombs. The cross sectional area will just be ##\pi(1.2∗10^−3)^2## m^2. Now we need to find the free electron density. We are given the density of of copper and can use dimensional analysis to find free electron density. Assume one free electron per copper atom:

$$\frac{8.92g}{cm^3} \times \frac{1 mol}{63.55g} \times \frac{6.022 \times 10^{23}atoms}{1mol} \times \frac{1 electron}{1 atom} = 8.45 \times 10^{22} \frac{electrons}{cm^3}$$

Plug in numbers

$$\frac{8.0 amps}{(\frac{8.45 \times10^{22}electrons}{cm^3})(1.6\times10^{-19}C)(\pi(1.2\times10^{-3})^2)}$$

I git 130.8 m/s but it was wrong. Can anyone help me find out why?
 
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Jaccobtw said:
We are given the density of of copper and can use dimensional analysis to find free electron density.
As much as I love dimensional analysis, it can never give you an exact relation. You can use it to check your answers and deduct the functional form of physical relations up to constants.

Also, 1.2e-3 m is not the same as 1.2e-3 cm.
 
Jaccobtw said:
Homework Statement:: A cylindrical copper wire has a radius of 1.2∗10^−3 m. It carries a constant current of 8.00A. What is the drift speed of the electrons in the wire in m/s? Assume each copper atom contributes one free electron to the current. The density of copper is 8.92g/cm^3.
.
Relevant Equations:: $$v_d = \frac{I}{neA}$$

We need to find each variable. ##I## is already given to us as 8 amps. The charge of an electron is 1.6 x 10^-19 coulombs. The cross sectional area will just be ##\pi(1.2∗10^−3)^2## m^2. Now we need to find the free electron density. We are given the density of of copper and can use dimensional analysis to find free electron density. Assume one free electron per copper atom:

$$\frac{8.92g}{cm^3} \times \frac{1 mol}{63.55g} \times \frac{6.022 \times 10^{23}atoms}{1mol} \times \frac{1 electron}{1 atom} = 8.45 \times 10^{22} \frac{electrons}{cm^3}$$

Plug in numbers

$$\frac{8.0 amps}{(\frac{8.45 \times10^{22}electrons}{cm^3})(1.6\times10^{-19}C)(\pi(1.2\times10^{-3})^2)}$$

I git 130.8 m/s but it was wrong. Can anyone help me find out why?
Carefully simplify the units in your answer. You have some mismatched units which don't "cancel" .
 
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