Fatima Hasan Messages 315 Reaction score 14 Thread starter Apr 11, 2018 #1 Homework Statement Homework Equations ##E=\frac{kQ}{r^2}## 3. The Attempt at a Solution ##Q_{enclosed} = 0 ## , because there is no charge inside the conducting cylinder. E = 0 Can anyone check my answer please ? Attachments screenshot_56.png 33.2 KB · Views: 799
Homework Statement Homework Equations ##E=\frac{kQ}{r^2}## 3. The Attempt at a Solution ##Q_{enclosed} = 0 ## , because there is no charge inside the conducting cylinder. E = 0 Can anyone check my answer please ?
Doc Al Mentor Messages 45,589 Reaction score 2,478 Apr 11, 2018 #2 Fatima Hasan said: because there is no charge inside the conducting cylinder. The point in question is not inside the conducting material. It's at a point 10 cm from the axis, well beyond the conducting shell.
Fatima Hasan said: because there is no charge inside the conducting cylinder. The point in question is not inside the conducting material. It's at a point 10 cm from the axis, well beyond the conducting shell.
Fatima Hasan Messages 315 Reaction score 14 Apr 11, 2018 #3 Doc Al said: The point in question is not inside the conducting material. It's at a point 10 cm from the axis, well beyond the conducting shell. Attachments rac%7B20*10%5E%7B-9%7D+12*10%5E%7B-9%7D%7D%7B2%5Cpi%20*8.85*10%5E%7B-12%7D*0.1%7D%20%3D%205.png 2.3 KB · Views: 382
Doc Al said: The point in question is not inside the conducting material. It's at a point 10 cm from the axis, well beyond the conducting shell.
Doc Al Mentor Messages 45,589 Reaction score 2,478 Apr 11, 2018 #4 Note that the charge on the conducting shell is negative.
Fatima Hasan Messages 315 Reaction score 14 Apr 11, 2018 #5 Doc Al said: Note that the charge on the conducting shell is negative. Attachments 7B20*10%5E%7B-9%7D-12*10%5E%7B-9%7D%7D%7B2%5Cpi%20%5Ccdot%208.85*10%5E%7B-12%7D*0.1%7D%20%3D%201.png 2.3 KB · Views: 396