Find the electric field at a point away from the charged cylinder's axis

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Fatima Hasan
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Homework Statement


screenshot_56.png


Homework Equations



##E=\frac{kQ}{r^2}##

3. The Attempt at a Solution

##Q_{enclosed} = 0 ## , because there is no charge inside the conducting cylinder.
E = 0
Can anyone check my answer please ?
 

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Fatima Hasan said:
because there is no charge inside the conducting cylinder.
The point in question is not inside the conducting material. It's at a point 10 cm from the axis, well beyond the conducting shell.
 
Doc Al said:
The point in question is not inside the conducting material. It's at a point 10 cm from the axis, well beyond the conducting shell.
rac%7B20*10%5E%7B-9%7D+12*10%5E%7B-9%7D%7D%7B2%5Cpi%20*8.85*10%5E%7B-12%7D*0.1%7D%20%3D%205.png
 

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    rac%7B20*10%5E%7B-9%7D+12*10%5E%7B-9%7D%7D%7B2%5Cpi%20*8.85*10%5E%7B-12%7D*0.1%7D%20%3D%205.png
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Note that the charge on the conducting shell is negative.
 
Doc Al said:
Note that the charge on the conducting shell is negative.
7B20*10%5E%7B-9%7D-12*10%5E%7B-9%7D%7D%7B2%5Cpi%20%5Ccdot%208.85*10%5E%7B-12%7D*0.1%7D%20%3D%201.png
 

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  • 7B20*10%5E%7B-9%7D-12*10%5E%7B-9%7D%7D%7B2%5Cpi%20%5Ccdot%208.85*10%5E%7B-12%7D*0.1%7D%20%3D%201.png
    7B20*10%5E%7B-9%7D-12*10%5E%7B-9%7D%7D%7B2%5Cpi%20%5Ccdot%208.85*10%5E%7B-12%7D*0.1%7D%20%3D%201.png
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Now you've got it.
 
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