Find the electric field at a point away from the charged cylinder's axis

In summary, the conversation discusses the electric field at a point outside a conducting cylinder, which is found to be zero due to the absence of charge inside the cylinder. The charge on the conducting shell is also mentioned, being negative.
  • #1
Fatima Hasan
319
14

Homework Statement


screenshot_56.png


Homework Equations



##E=\frac{kQ}{r^2}##

3. The Attempt at a Solution

##Q_{enclosed} = 0 ## , because there is no charge inside the conducting cylinder.
E = 0
Can anyone check my answer please ?
 

Attachments

  • screenshot_56.png
    screenshot_56.png
    33.2 KB · Views: 677
Physics news on Phys.org
  • #2
Fatima Hasan said:
because there is no charge inside the conducting cylinder.
The point in question is not inside the conducting material. It's at a point 10 cm from the axis, well beyond the conducting shell.
 
  • #3
Doc Al said:
The point in question is not inside the conducting material. It's at a point 10 cm from the axis, well beyond the conducting shell.
rac%7B20*10%5E%7B-9%7D+12*10%5E%7B-9%7D%7D%7B2%5Cpi%20*8.85*10%5E%7B-12%7D*0.1%7D%20%3D%205.png
 

Attachments

  • rac%7B20*10%5E%7B-9%7D+12*10%5E%7B-9%7D%7D%7B2%5Cpi%20*8.85*10%5E%7B-12%7D*0.1%7D%20%3D%205.png
    rac%7B20*10%5E%7B-9%7D+12*10%5E%7B-9%7D%7D%7B2%5Cpi%20*8.85*10%5E%7B-12%7D*0.1%7D%20%3D%205.png
    2.3 KB · Views: 284
  • #4
Note that the charge on the conducting shell is negative.
 
  • #5
Doc Al said:
Note that the charge on the conducting shell is negative.
7B20*10%5E%7B-9%7D-12*10%5E%7B-9%7D%7D%7B2%5Cpi%20%5Ccdot%208.85*10%5E%7B-12%7D*0.1%7D%20%3D%201.png
 

Attachments

  • 7B20*10%5E%7B-9%7D-12*10%5E%7B-9%7D%7D%7B2%5Cpi%20%5Ccdot%208.85*10%5E%7B-12%7D*0.1%7D%20%3D%201.png
    7B20*10%5E%7B-9%7D-12*10%5E%7B-9%7D%7D%7B2%5Cpi%20%5Ccdot%208.85*10%5E%7B-12%7D*0.1%7D%20%3D%201.png
    2.3 KB · Views: 295
  • #6
Now you've got it.
 
  • Like
Likes Fatima Hasan

What is the formula for finding the electric field at a point away from the charged cylinder's axis?

The formula for finding the electric field at a point away from the charged cylinder's axis is E = kλ/r, where E is the electric field, k is the Coulomb's constant, λ is the charge per unit length of the cylinder, and r is the distance from the cylinder's axis.

What are the units of the electric field?

The units of the electric field are newtons per coulomb (N/C) in the SI system. In other systems, it can also be expressed as volts per meter (V/m) or teslas (T).

How does the magnitude and direction of the electric field depend on the distance from the cylinder's axis?

The magnitude of the electric field decreases as the distance from the cylinder's axis increases. The direction of the electric field is always perpendicular to the cylinder's axis and points away from the positive charge and towards the negative charge.

Can the electric field at a point away from the cylinder's axis be zero?

Yes, the electric field can be zero at a point away from the cylinder's axis if the distance from the axis is infinity or if the charge per unit length of the cylinder is zero.

What is the significance of finding the electric field at a point away from the cylinder's axis?

Finding the electric field at a point away from the cylinder's axis can help us understand the behavior of electric charges in the vicinity of the cylinder. It is also important in practical applications such as designing electrical systems or calculating the force on a charged particle near the cylinder.

Similar threads

  • Introductory Physics Homework Help
Replies
3
Views
215
  • Introductory Physics Homework Help
Replies
17
Views
401
  • Introductory Physics Homework Help
Replies
2
Views
1K
  • Introductory Physics Homework Help
Replies
7
Views
2K
  • Introductory Physics Homework Help
Replies
4
Views
3K
  • Introductory Physics Homework Help
Replies
26
Views
583
  • Introductory Physics Homework Help
Replies
5
Views
698
  • Introductory Physics Homework Help
Replies
5
Views
807
  • Introductory Physics Homework Help
Replies
4
Views
2K
  • Introductory Physics Homework Help
Replies
2
Views
1K
Back
Top