Find the energy stored in a spring at .05m and .10m

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SUMMARY

The energy stored in a spring can be calculated using the formula F = 1/2 k x^2, where k is the spring constant and x is the displacement from the equilibrium position. For a spring constant of 67.21 N/m, the energy stored at a displacement of 0.05m is 0.0841 Joules, and at 0.10m, it is 0.3364 Joules. This calculation is essential for understanding the potential energy stored in elastic materials.

PREREQUISITES
  • Understanding of Hooke's Law
  • Familiarity with the formula for elastic potential energy
  • Basic knowledge of units of energy (Joules)
  • Ability to perform calculations involving squares of numbers
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  • Review the derivation of Hooke's Law and its applications
  • Explore the concept of elastic potential energy in different contexts
  • Learn about the implications of spring constants in real-world applications
  • Investigate graphical representations of force vs. displacement
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Students studying physics, particularly those focusing on mechanics and energy concepts, as well as educators looking for practical examples of spring energy calculations.

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Homework Statement


Find the energy stored in a spring when stretched .05m, and .10m. Spring Constant of 67.21 N/m.

(I am given a graph)


Homework Equations


F=1/2kx^2


The Attempt at a Solution


Ok, to find the energy stored I believe I am going to need the distance (.05m, and .10m) and the spring constant. Is there a way to calculate energy stored with just this? I am given a graph but the Force vs. Distance (in meters) only goes up to 0.3m so I can't rely on the graph just by looking at it.
 
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