Find the Final Temperature of Metal and Water in a Thermodynamics Problem

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A thermodynamics problem involves a 100-g piece of metal at 75°C submerged in 100 g of water at 25°C, requiring the calculation of the final temperature. The specific heat capacities are given as 0.45 J g-1 °C-1 for iron and 4.18 J g-1 °C-1 for water. The equation q=mc(delta T) is used to set up the heat transfer equation, but an error was identified in the temperature change terms. The metal loses heat, so the correct equation should reflect the temperature change as (75 - Tfinal) for the metal. Understanding this adjustment leads to the correct solution for the final temperature.
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1. Homework Statement
A 100-g piece of metal initially at T = 75oC is submerged in 100 g of water initially at T = 25oC. The specific heat capacity of iron is 0.45 J g-1 °C-1 and the specific heat capacity of water is 4.18 J g-1 °C-1. What is the final temperature of both substances in oC?


2. Homework Equations
q=mc(delta T)


3. The Attempt at a Solution
well i tried to set mc(delta T)=mc(delta T), plug in all the values and solve for T(final), but i keep getting the wrong answer
 
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What numbers did you put for each of the changes in temperature?
 
mc(delta T)=mc(delta T)

(100)(.45)(T(final)-75)=100(4.184)(T(final)-25)

i solved that for T(final) but still got the wrong answer
 
physicsman2 said:
mc(delta T)=mc(delta T)

(100)(.45)(T(final)-75)=100(4.184)(T(final)-25)

i solved that for T(final) but still got the wrong answer


For the term on the left side, (the metal at 75), it can't gain heat, it only loses heat. So That should be (75-Tfinal). Understand?
 
oh, now i understand, thank you so much
 
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