- #1
TSN79
- 424
- 0
A function with a period T=2 is defined as [tex]f(x)=\left\{\begin{array}{cc}-1-x,&\mbox{ if }
-1\leq x<0\\1-x, & \mbox{ if }0\leq x<1\end{array}\right[/tex]
I'm supposed to find the Fourier-sequence. When trying to find [tex]b_n[/tex] the expression becomes [tex]b_n=\int_{0}^{1} f(x)*sin(n*\omega*x)dx[/tex]
[tex]\omega=\pi[/tex] My book says [tex]f(x)*sin(n*\omega*x)[/tex] is an even function, which I can't understand. Doesn't that mean that it should be symetrical about the y-axis? I can't see that it is. What am I not doing right here?
-1\leq x<0\\1-x, & \mbox{ if }0\leq x<1\end{array}\right[/tex]
I'm supposed to find the Fourier-sequence. When trying to find [tex]b_n[/tex] the expression becomes [tex]b_n=\int_{0}^{1} f(x)*sin(n*\omega*x)dx[/tex]
[tex]\omega=\pi[/tex] My book says [tex]f(x)*sin(n*\omega*x)[/tex] is an even function, which I can't understand. Doesn't that mean that it should be symetrical about the y-axis? I can't see that it is. What am I not doing right here?