Find the general solution for a nonhomogenous equation.

cyturk
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Homework Statement


Find the general solution for a nonhomogenous equation.
y''+4y=3csc2t

Homework Equations


The Attempt at a Solution


I simplified the equation to...
y''+4y=(3)/(sin(2t))

Then I guessed...
y=Asint+Bcost
y'=Acost-Bsint
y''=-Asint-BcostThen I got...
-Asint-Bcost+4Asint+4Bcost=(3)/(sin(2t))

Simplifies to...
3Asint+3Bcost=(3)/(2sintcost))

NOTE: Trig Identity: sin(2t)=2sintcost

I am stuck and I am not even sure if I took the correct steps.
 
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Variations of parameters.
 
hunt_mat said:
Variations of parameters.

Thanks for your help! I have been trying to figure out Variation of Parameters and I can't seem to find it on Khan Academy. Any chance there are any videos or resources you can suggest?
 
http://en.wikipedia.org/wiki/Variation_of_parameters" is always a good place as sometimes they'll give an example...like in what I posted.
 
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Thanks for everyone's help! I got a solution, although it kinda looks weird, but it makes sense to me now! :)
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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