Engineering Find the hysteresis loss in the magnetic material

AI Thread Summary
The discussion confirms that the hysteresis energy loss is 300 joules per cycle per cubic meter at a maximum flux density of 1.2 T, leading to an area of the hysteresis loop of 300. The formula used for calculating power loss (Ph) is Ph = A * V * f, resulting in a power loss of 300 W for a volume of 1 m³ at 1 Hz. The value of Kh is calculated to be 224.09, which is used to find Ph at a lower flux density of 0.8 T, frequency of 60 Hz, and a volume of 40 cm³. The final calculation confirms that Ph equals 0.376 W, validating the computations presented. Overall, the calculations and results for hysteresis loss are affirmed as correct.
Fatima Hasan
Messages
315
Reaction score
14
Homework Statement
A sample of a magnetic material is known to have a hysteresis energy loss of 300 joules per cycle per cubic meter when the maximum flux density is 1.2 T . Find the hysteresis loss in the magnetic material if the flux density is 0.8 T , the volume of the magnetic material is 40 cm^3 , and the frequency of operation is 60 Hz . The Steinmetz constant is 1.6.
Relevant Equations
Equations are attached below.
5E%7B-6%7D%29*0.8%5E%7B1.6%7D%20%5C%5C%5C%5C%3D156.gif


That's what I've got , but I want to confirm my answer.
Any help would be greatly appreciated !
 

Attachments

  • Equations.gif
    Equations.gif
    1.5 KB · Views: 383
Physics news on Phys.org
Since the hysteresis energy loss is 300 joules per cycle per cubic meter when the maximum flux density is 1.2 T , the area of the hysteresis loop should be 300 at maximum flux density is 1.2 T, which means that just A=300.
:flashlight:
 
alan123hk said:
Since the hysteresis energy loss is 300 joules per cycle per cubic meter when the maximum flux density is 1.2 T , the area of the hysteresis loop should be 300 at maximum flux density is 1.2 T, which means that just A=300.
:flashlight:
So ,
Ph = A *V *f
V = 1 m^3
f = 1 Hz
A = 300 joules/ m^3 cycle
Ph = 300 W
Ph = Kh * f * Bmax^n * V
300 = Kh * 1*1.2^(1.6)*1
Solve for Kh = 224.09
Ph when the flux density = 0.8 T , f=60 Hz and V = 40 cm^3 :
Ph = 224.09 * 60 * (0.8)^1.6 * 40*10^(-3)
Ph = 0.376 W
Am I right now ?
 
Yes, I agree that Ph = 224.09 * 60 * (0.8)^1.6 * 40*10^(-6) = 0.376W is correct.
 
  • Like
Likes Fatima Hasan
alan123hk said:
Yes, I agree that Ph = 224.09 * 60 * (0.8)^1.6 * 40*10^(-6) = 0.376W is correct.
Thank you for your reply .
 
Back
Top