Find the induced magnetic current on the inner of two rings

AI Thread Summary
The discussion revolves around calculating the induced current in a small circular loop placed at the center of a larger loop, as the current in the outer loop changes from +1A to -1A. The user attempts to apply relevant equations, including those for magnetic flux and induced current, but arrives at an incorrect answer of 3590 nA instead of the correct 4.79 nA. Key formulas discussed include the calculation of magnetic field (B), magnetic flux (Φ), and induced voltage (V). The user seeks clarification on the discrepancy in their calculations and the correct approach to determine the induced current. Understanding the correct application of Faraday's law and the relationship between changing magnetic fields and induced currents is crucial for solving this problem accurately.
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Homework Statement


A small, 1.60-mm-diameter circular loop with R = 1.10×10−2Ω is at the center of a large 120-mm-diameter circular loop. Both loops lie in the same plane. The current in the outer loop changes from + 1A to -1A in 8.00×10^−2s .

What is the induced current in the inner loop? in nA

Homework Equations



I=ε/R
ε=Phi/t
Phi=A*B

The Attempt at a Solution



I=ε/R

Phi=(Area)*(Magnitude of field)
Phi = (PI*(8x10^-4^2 m^2)*??)

I am completely unsure of what to do after this. Please help! Thanks.
 
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Ok, I tried this:

B=mu*I/2R

B1=4PIx10^-7 * +1 / 2*(1.1x10^-2)= 0.000785 T

B2=4PIx10^-7 * -1 / 2*(1.1x10^-2)= -0.000785 T

I=V/R

V=PHI1-PHI2/t

PHI1=A*B1

PHI1=PI*(8x10^-4)^2 * 0.000785 =1.58x10^-9

PHI2=A*B2=PI*(8x10^-4)^2 * - 0.000785=-1.58x10^-9

V=(1.58x10^-9)*2/(8x10^-2)
V=3.95x10^-8

I=V/R

I=(3.95x10^-8)/(1.1x10^-2)
I=3.59x10^-6 A =3590 nA

Yes?I submitted, but this was not correct. The correct answer was 4.79 nA. Can anyone please explain how?
 
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