Find the initial velocity of truck before collision

AI Thread Summary
To find the initial velocity of the truck before the collision, the conservation of momentum equation is applied: m1v1 + m2v2 = m1v1' + m2v2'. Given the car's mass of 1500 kg and speed of 30 m/s, while the truck's mass is 9000 kg, the equation simplifies to (1500 kg)(30 m/s) + (9000 kg)(v2) = 0. The calculation shows that the truck's initial velocity must be negative, indicating it was moving in the opposite direction to the car. The confusion arises from interpreting the negative value, which correctly reflects the truck's motion relative to the car.
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Question: A car of mass 1500kg collides head-on with a truck of mass 9000kg. After the collision, the wreckage is at rest. The speed of the car just before the collision was 30m/s. What was the speed of the truck just before the collision?

Relevant Equation(s):

m1v1+m2v2 = m1v1'+m2v2' (?)

My Attempt:

(1500kg)(30m/s)+(9000kg)( ___m/s) = (1500kg)(0m/s)+(9000kg)( 0m/s)
(1500kg)(30m/s)+(9000kg)( ___m/s) = 0
(45000 kg*m/s)+(9000kg)(___m/s) = 0

Problem: It's 1 in the morning and I'm not understanding what I'm doing wrong. Am I using the right equation? Do I need to set up west and east on the x-axis??
 
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Why do you think you are doing something wrong? You will get a negative answer, but that only tells you the truck is moving in the opposite direction of the car.
 
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