Struggling with Integrals? Don't Panic, Here's Some Tips!

  • Thread starter 1MileCrash
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In summary: Anyway, back to the problem at hand. According to Mark44's expression, cos(2x) = 1 - 2 sin2(x). So, cos(2x) = 1 - 1/2 sin2(x). This is true for all x.Now, let's take a look at the second half of Mark44's expression: cos2(x) = cos2(x) + sin2(x). This is also true for all x. Therefore, cos2(x) = 1 + 1/2 sin2(x). This is also true for all x. Therefore, cos2(x) = 2 sin2(x).Finally, we can solve for sin
  • #1
1MileCrash
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Homework Statement



[itex]\int sin^{2}x dx[/itex]

Homework Equations





The Attempt at a Solution



I don't see why. Clearly it is designed for me to shoot myself before finishing.

u = (sinx)^2
du = 2sinxcosx dx, magically equal to sin2x dx
v = x
dv = dx

(-xcos2x/2) + (sin2x/4)

=

(-2xcos2x+sin2x)/(4) + C = wrong
 
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  • #2
Since you just reviewed the double angle formula for sin, what's the double angle formula for cos?

cos(2x) = ? = ? = ?

Yes, there are three forms. One will work quite nicely here.
 
  • #3
Firstly, let me apologize for my attitude. Secondly, thanks for the tip, I'll work it again and post back.
 
  • #4
At times, getting frustrated can lead to good things.
 
  • #5
[itex]\int sin^{2}x dx[/itex]

[itex]u = sin^{2}x[/itex]
[itex]du = sin2x dx[/itex]
[itex]v = x[/itex]
[itex]dv = dx[/itex]

[itex]xsin^{2}x - \int xsin2x dx[/itex]

[itex]u = x[/itex]
[itex]du = dx[/itex]
[itex]v = -\frac{cos2x}{2}[/itex]
[itex]dv = sin2x dx[/itex]

[itex]xsin^{2}x - [-\frac{xcos2x}{2} - \int -\frac{cos2x}{2} dx ][/itex]
[itex]xsin^{2}x - [-\frac{xcos2x}{2} + \frac{sin2x}{4}][/itex]

[itex]xsin^{2}x + \frac{xcos2x}{2} - \frac{sin2x}{4}[/itex]

[itex] \frac{2xsin^{2}x + xcos2x}{2} - \frac{sin2x}{4}[/itex]


[itex] \frac{2xsin^{2}x + x(cos^{2}x - sin^{2}x)}{2} - \frac{sin2x}{4}[/itex]


[itex] \frac{2xsin^{2}x + xcos^{2}x - xsin^{2}x}{2} - \frac{sin2x}{4}[/itex]


[itex] \frac{xsin^{2}x + xcos^{2}x}{2} - \frac{sin2x}{4}[/itex]


[itex] \frac{x(sin^{2}x + cos^{2}x)}{2} - \frac{sin2x}{4}[/itex]


[itex] \frac{x}{2} - \frac{sin2x}{4}[/itex]
 
  • #6
There's a much shorter way of doing this, following Sammy's hint.

sin2(x) = 1/2 * (1 - cos(2x))

This will give you an integral that you can do without having to resort to integration by parts.
 
  • #7
Mark44's expression comes from solving the following for sin2(x) .

cos(2x) = 1 - 2 sin2(x) .

It's also true that

cos(2x) = cos2(x) - sin2(x)

cos(2x) = 2 cos2(x) - 1
 
  • #8
1MileCrash said:
Firstly, let me apologize for my attitude.

th_smiley-bangheadonwall.gif


Welcome to the wonderful world of integrals! There are times when I want to kick small, defenseless animals because of this stuff. I usually listen to some thrash metal while studying math. I don't know why, but it helps!

Try to remember as many identities as you possibly can. It makes life a lot easier.
 

1. What is the purpose of finding the integral of annoying?

The purpose of finding the integral of annoying is to understand and quantify the level of annoyance that a particular situation or person may cause. It can also help in finding ways to reduce or eliminate the source of annoyance.

2. How is the integral of annoying calculated?

The integral of annoying is calculated by evaluating the integral of the function that represents the level of annoyance over time. This integral represents the total amount of annoyance experienced over a given period of time.

3. Can the integral of annoying be negative?

Yes, the integral of annoying can be negative. This can happen if there are moments of relief or calmness during the period of time being evaluated. In this case, the negative integral would represent the reduction in annoyance experienced.

4. Is the integral of annoying a subjective measurement?

Yes, the integral of annoying is a subjective measurement as it is based on an individual's perception of annoyance. What may be annoying to one person may not be to another, so the integral may vary from person to person.

5. What are some real-world applications of finding the integral of annoying?

Finding the integral of annoying can be useful in various fields such as psychology, customer satisfaction, and product design. It can also be used in personal development to identify and address sources of annoyance in one's life.

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