• Support PF! Buy your school textbooks, materials and every day products Here!

Find the magnitude of the electric field at the center

  • #1
1. Homework Statement

The magnitude of each of the charges in the figure is 9.00x10^-12 C. The lengths of the sides of the rectangle are 3.00 cm and 6.00 cm. Find the magnitude of the electric field at the center of the rectangle in figures a and b.

http://www.webassign.net/CJ/18-21fig.gif



2. Homework Equations

E=kq/r^2



3. The Attempt at a Solution



For part A, I attempted to use the equation E=kq/r^2 to find the magnitude of E24 since that is all that is contributing to the electric field because of the fact that the charges at corner 1 and corner 3 are both positive and will cancel each other out. I used the pythagorean theorum to find the length of the hypotenuse (which I used as the r in the equation) of the right triangle that is created with the line between E24 and the sides of 3 cm and 6 cm to come up with a value of 6.708 which converts to .06708 meters.

E=[(8.99x10^9)(9.00x10-12)]/(.06708)^2 = 17.98 N/C I don't believe this answer is correct and this is where I have been stuck for the last few hours trying to figure out what I've done wrong.

For part B, I have no idea how to proceed because I will need the work from part A to go any further. Any guidance would be greatly appreciated!
 

Answers and Replies

  • #2
marcusl
Science Advisor
Gold Member
2,684
353
6.7 is the length across the rectangle. You want half that distance...
 
  • #3
That comes out to 71.92 N/C, which still isn't the correct answer. Are my set-up and equations correct?
 
  • #4
Okay, I was able to answer part a of the problem (143.84 N/C), but I'm having some trouble with the second part of the problem and hoping that someone can assist me. I believe the angle that I need to use to calculate the x and y components is 26.6 degrees. There also is not an x component to this problem, since the field only points in the y direction. But this is where I reach the point where I don't know how to proceed next?
 
  • #5
Same problem, Different Values

hi,

i have a similar problem, but my problem is:
The magnitude of each of the charges in the figure is 8.00 10-12 C. The lengths of the sides of the rectangle are 3.00 cm and 4.00 cm. Find the magnitude of the electric field at the center of the rectangle in figures a and b.
I can't figure out how either parts are done. Can you show me what you did for part a and/or b?

thanks,

DeucesZ
 
  • #6
Alright here is what you need to do. Once this finished you can put it in the archives for other struggling students...

In order to get the force you will need to use the electric field equation. E=kq/(distance). To get the distance you will need to do the following: convert the units to meters. Form a pythagorean triangle. Find the hypontenuse. Which for deuceszbigz is .05m Square root it. .0025. Plug into equation with charge and k. Get a value you will need to double because there is a positive charge pushing it just as much as the electric charge is pulling it.
That will get you a. For b life sucks and gets ultra tricky. You will need to do pythagorean theorem for the entire rectangle. So you have a 3,4,5 triangle and you know the hypotense. Calculate angles using SOH CAH TOA. Now you have an angle. Use your previous answer and multiply it by sin of the angle you discover (37 degrees) and multiply that by two and you got your answer.
 

Related Threads for: Find the magnitude of the electric field at the center

Replies
4
Views
7K
Replies
2
Views
2K
Replies
22
Views
3K
Replies
1
Views
34K
Replies
1
Views
4K
Top