Find the magnitude of the electric field in the capacitor

AI Thread Summary
To find the magnitude of the electric field in a parallel-plate capacitor, the electric force on the electron must be determined using Newton's second law. The deflection of the electron by 0.594 cm can be analyzed through kinematic equations, similar to projectile motion. The initial speed of the electron is given as 5.20 x 10^-6 m/s, which will also be needed to calculate its final speed upon exiting the capacitor. By applying these principles, the required calculations can be performed to solve for both the electric field strength in N/C and the electron's speed in m/s. Understanding the relationship between electric force, acceleration, and motion is crucial for solving the problem.
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Homework Statement


An electron entering a parallel-plate capacitor with a speed of v=5.20 x 10^-6 m/s. The electric field of the capacitor has deflected the electron downward by a distance of d=0.594cm at the point where the electron exists the capacitor.
a)find the magnitude of the electric field in the capacitor____N/C
b)find the speed of the electron when it exists the capacitor___m/s


Homework Equations





The Attempt at a Solution



I have no clue how to start this problem
 
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What's the electric force on a charge in an electric field? Apply this to Newton's second law.

Then think about your kinematic equations (like in projectile motion).
 

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