Find the magnitude of the force that stops the bullet

AI Thread Summary
The discussion focuses on calculating the force that stops a bullet and the time it takes for the bullet to stop after penetrating a tree trunk. Using the work-energy theorem, the force is determined to be 22,500 N by equating the bullet's kinetic energy to the work done against the stopping force. For the time calculation, the acceleration is derived from the force and mass of the bullet, leading to a stopping time of approximately 0.000133 seconds. The importance of unit conversion is emphasized throughout the calculations. The final results confirm the accuracy of the derived values for force and time.
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HELP Please!

Ok, I am totally lost on how to solve this problem: A 5 g bullet moving at 600 m/s penetrates a tree trunk to a depth of 4 cm.
a. use work and energy considerations to find the magnitude of the force that stops the bullet
b. assuming that the frictional force is constant, determine how much time elapses between the moment the bullet enters the tree trunk and the moment the bullet stops moving.

I know the answers are 2.25*10^4 N, and 1.33*10^4 s, but I have no idea how to get them
 
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a) Using the work energy theorem we get taht...
* remember to convert the units

<br /> \frac{1}{2}(0.005)(600)^2 = F(0.04)<br />

Solving for F gives 22500N
 
Thanks, I really was lost because of the "depth" part.
 
b)

m = 0.005
F = 22500N

a = F/m
a = (v-u)/t

that gives
t = (v-u)/a

v = 0
u = 600

so.. i found that:
t = 0.000133333333

So you see :)
 
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