Find the max speed so that an electron doesn't hit the plate

AI Thread Summary
The discussion focuses on calculating the maximum initial velocity (V0) of an electron fired at a 45-degree angle between two parallel plates, ensuring it does not hit the upper plate. The electric field strength is given as 103 N/C, and the separation between the plates is 2 cm. The acceleration of the electron is calculated to be -1.76 x 10^14 m/s². Participants suggest using kinematic equations, particularly considering that the vertical velocity must be zero at the peak of the electron's trajectory to avoid collision. Ultimately, the maximum initial velocity is determined to be 3.75 x 10^6 m/s.
Whiteclaws

Homework Statement



An electron is fired from x = 0 with an unknown V0 at 45 degs to the horizontal between two parallel plates separated by 2 cm. Electric field is 103 j N/C. Find:

a) The max value of V0 so that the electrons don’t hit the upper plate
3.75 * 106 m/s

Homework Equations


If you find acceleration, it is essentially a kinetics problem
Eq = ma

The Attempt at a Solution


a = -1.76 * 10^14 j m/s^2
0.02 = v0t -8.8 * 10^13 t^2
Then I have no idea how to solve for either t or V0,
For anybody who has the book university physics, it's number 33
 
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Whiteclaws said:
0.02 = v0t -8.8 * 10^13 t^2
Is the initial velocity in the upward direction Vo? What do you know from the given 45° angle?
Whiteclaws said:
Then I have no idea how to solve for either t or V0,
You need one more equation if you want to involve time.
Instead, you can solve it with only one equation.
If initial vertical velocity is at its maximum (so that the electron doesn't "hit" the upper plate), what should be the final velocity?
 
Last edited:
cnh1995 said:
Is the initial velocity in the upward direction Vo? What do you know from the given 45° angle?

You need one more equation if you want to involve time.
Instead, you can solve it with only one equation.
If initial vertical velocity is at its maximum (so that the electron doesn't "hit" the upper plate), what should be the final velocity?
V0 is a vector but for simplicity's sake let's assume that it's Vy initial
I'll convert it later
 
I SEE, IF V0 IS MAXIMIZED, THAT MEANS THAT VY AT THE TOP IS 0, SINCE IT'S AN ARC! SO
V^2 = v0^2 + 2adelta y
0 = (Vosin45)^2 + 2a delta y
and you SOLVE FOR VO!
thanks for the HINT!
 
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