Find the molarity and ph of diluted HCl

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    Hcl Molarity Ph
AI Thread Summary
To find the molarity and pH of diluted HCl, first determine the total volume of the solution by adding the volumes of distilled water and HCl. The molarity is calculated by dividing the moles of HCl (derived from the concentration and volume of the HCl added) by the total volume in liters. The discussion clarifies that molarity is defined as moles of solute per liter of solution, not just moles over volume. For pH, it's essential to recognize that HCl is a strong acid and will fully ionize in solution. Understanding these calculations is crucial for solving the homework problem effectively.
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Homework Statement


To 25.000 mL of distilled water in a 50 mL beaker, you add exactly 19 drops of 0.100 M HCl and swirl to mix. If exactly 20 drops of HCl are required to make 1.000 mL


Homework Equations


Calculate molarity of the diluted HCl and pH of the diluted HCl



The Attempt at a Solution


i really don't know where to start.
i'd really appreciate the help i can get
 
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What is the final volume of the solution? How many moles of HCl are in 19/20 mL of 0.100 M HCl? What is the definition of molarity and how can you calculate pH if you know the molarity of the acid?
 
19/20 ml of HCL? you mean the drops
what about .025L or .001L isn't that the vol. for HCl
all i know is molarity is moles/volume
i'm still lost. since there's two volumes given and no moles to do the molarity equation
 
If you add 50 mL to 1 mL how many mL is the final solution? Now do that for 25 mL plus 19/20 mL... That's final volume.

Know how to calculate molarity? It's not moles/volume, btw.
 
Molarity means moles of substance of interest per liter of solution.

Use your given information to calculate moles of HCl added;
The volume of resulting solution is the sum of the volume of the individual volumes of everything added to make the solution. You want "Moles of HCl per liter of solution".

Note that for pH question, you want to know what pH means; and know that your HCl is essentially completely ionized in aqueous solution.
 
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