Find the radius of each circular path

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SUMMARY

The discussion centers on calculating the radius of the circular path of an electron moving at a speed of 2.5 x 105 m/s at a 30-degree angle in a magnetic field. Participants highlight the need for the magnetic field strength (B) to determine the radius, as the force acting on the electron is given by F = qvB and the centripetal force is F = mv2/r. Without the value of B, the calculation remains incomplete, indicating that additional information is necessary to solve the problem accurately.

PREREQUISITES
  • Understanding of electromagnetic force (F = qvB)
  • Knowledge of centripetal force equations (F = mv2/r)
  • Basic concepts of electron motion in magnetic fields
  • Ability to resolve vector components (e.g., velocity at an angle)
NEXT STEPS
  • Research the relationship between magnetic field strength and electron motion
  • Learn how to calculate the radius of circular motion in magnetic fields
  • Explore the Lorentz force law and its applications
  • Study examples of charged particle trajectories in magnetic fields
USEFUL FOR

Students studying electromagnetism, physics educators, and anyone interested in the dynamics of charged particles in magnetic fields.

Canuck269
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Homework Statement



Determine the path of an electron if the electron was shot at 2.5 x 10^5 m/s diagonally into a magnetic field. Find the radius of each circular path.

The angle is 30 degrees.I think that if the velocity and field are in same direction there is no force...i think. So that means you only want the component perpendicular to the field. Which is 1.25 x 10^5 m/s

I just don't understand how you can find the radius if you are given no info about the magnetic field. F= qvB and F= m v^2/r So I tried putting that together but I still have 2 variables...

The question was listed as challenger :P So I don't think it's missing info.
 
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you need info about the B-field or some other observations about the path of the electron.
 

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