Find the vertical distance between point, and quation?

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The discussion focuses on finding the vertical distance between the point A(−2,−3) and the line represented by the equation 2x + 5y = 3. The user attempts to convert the line equation into slope-intercept form, resulting in y = 2/5x - 3/5, and then plots the point and the line. They calculate the vertical distance using the distance formula, arriving at a value of 1.6, but express uncertainty about their arithmetic. Another participant suggests checking the calculations, indicating a possible error in the equation transformation. The conversation emphasizes the importance of accurate arithmetic and proper equation manipulation in solving the problem.
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Homework Statement



What is the vertical distance between the point A(−2,−3) and the line 2x+5y=3.

Homework Equations





The Attempt at a Solution



Here is what I did: I know its wrong.

First, changed the equation into proper form:

y = 2/5x - 3/5

Plotted the equation...

Then, I drew in the point (-2,-3). Then drew line from point, vertically to the line, just as a graphical representation.

so from the line, x = -2

So, If x = -2, then y would equal -1.4

So, then I put this into the distance formula:

\sqrt{}(-2 - (-2))^2 + (-1.4 - (-3))^2

Which gave me 1.6
 
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nukeman said:

Homework Statement



What is the vertical distance between the point A(−2,−3) and the line 2x+5y=3.


Here is what I did: I know its wrong.

First, changed the equation into proper form:

y = 2/5x - 3/5

Check your arithmetic right there.
 
Oh...

Is this correct then?

y = -2/5x + 3/5?
 
I picked up this problem from the Schaum's series book titled "College Mathematics" by Ayres/Schmidt. It is a solved problem in the book. But what surprised me was that the solution to this problem was given in one line without any explanation. I could, therefore, not understand how the given one-line solution was reached. The one-line solution in the book says: The equation is ##x \cos{\omega} +y \sin{\omega} - 5 = 0##, ##\omega## being the parameter. From my side, the only thing I could...
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