Find the vertical distance between point, and quation?

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SUMMARY

The vertical distance between the point A(−2,−3) and the line represented by the equation 2x + 5y = 3 is calculated using the distance formula. The correct form of the line is y = -2/5x + 3/5. The distance was computed by finding the y-coordinate of the line at x = -2, which is -1.4, and then applying the distance formula to yield a vertical distance of 1.6 units. The initial attempt at solving the problem contained an arithmetic error in the line equation transformation.

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Homework Statement



What is the vertical distance between the point A(−2,−3) and the line 2x+5y=3.

Homework Equations





The Attempt at a Solution



Here is what I did: I know its wrong.

First, changed the equation into proper form:

y = 2/5x - 3/5

Plotted the equation...

Then, I drew in the point (-2,-3). Then drew line from point, vertically to the line, just as a graphical representation.

so from the line, x = -2

So, If x = -2, then y would equal -1.4

So, then I put this into the distance formula:

[itex]\sqrt{}(-2 - (-2))^2 + (-1.4 - (-3))^2[/itex]

Which gave me 1.6
 
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nukeman said:

Homework Statement



What is the vertical distance between the point A(−2,−3) and the line 2x+5y=3.


Here is what I did: I know its wrong.

First, changed the equation into proper form:

y = 2/5x - 3/5

Check your arithmetic right there.
 
Oh...

Is this correct then?

y = -2/5x + 3/5?
 

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