Find Thermal Energy & Initial Speed of Skidding 1200kg Car

AI Thread Summary
A 1200kg car with a coefficient of friction of 0.45 skids for 45.2 meters, prompting a calculation of thermal energy and initial speed. The frictional force is calculated as 5292 N, leading to a work done of 239198.4 J. However, the textbook indicates the thermal energy should be 5.3 kJ, and the initial speed is 72 km/h. The work-energy principle explains that the work done translates to thermal energy loss. Clarification on the relationship between work and thermal energy is provided, affirming their equivalence in value.
bigmac
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Homework Statement



A 1200kg car skids with uk = 0.45. If it skids 45.2m, find the thermal energy and the initial speed.

m = 1200 kg
Vi = ?
Vf = 0 m/s (i think..because it wants to stop)
uk = 0.45 (coefficient of friction)
delta d = 45.2m

Homework Equations



Well for Frictional force we use Ff = uk x Fn (0.45x11760) = 5292N


The Attempt at a Solution



So I found the Fn which is 1200 x 9.8 = 11760 N

Then I found Ff which is 0.45 x 11760 = 5292 N

Then I found the work done (I don't know why thermal energy is the work can someone explain this please)

W = F x d = 5292 x 45.2 = 239198.4 J

But my textbook's answer key has a different answer for the thermal energy, it says it should be 5.3 kJ and 72km/h for the speed. How do we find the speed?
 
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bigmac said:
I don't know why thermal energy is the work can someone explain this please

Hi bigmac! :smile:

work done = loss in energy (the work-energy equation), and nearly all the energy lost is thermal. :wink:

So they're different things, but they're equal in value.

And once you have the thermal energy, you can equate it to ∆(KE) :smile:
… W = F x d = 5292 x 45.2 = 239198.4 J

But my textbook's answer key has a different answer for the thermal energy, it says it should be 5.3 kJ and 72km/h for the speed. How do we find the speed?

Are you sure it doesn't say 5.3 kN ? :confused:

Using your figure for W, I do get 72km/h for the speed.
 
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