Find Tolerance Limit for f(x)=x^2.5 Near 0

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Homework Statement



Consider f(x)=x^2.5. Note that limf(x) as x->0+ =0. The input must be less than ___ from 0 to guarantee the output is within 0.1 of the limit.

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The Attempt at a Solution

 
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If I'm correct, the output can be 0.1 and -0.1. So I have computed:
f(0.1)= 0.00316 and f(-0.1)= -0.00316
These are the inputs that guarantee the output to be within 0.1 of the limit, 0. However, I think there is an error in my thinking somewhere.
 
You used 0.1 as an input.

Solve f(x-0) = 0 + 0.1 for x.
 
Ohhh okay! Got it. Thank you so much.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
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