Find Total Capacitance of Cube w/12 4.71pF Capacitors

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To find the total capacitance of a cube formed by 12 capacitors, each with a capacitance of 4.71 pF, it is suggested to first understand a simpler problem involving a cube of resistors. Writing node equations for the 8 vertexes of the resistor cube can provide insight into the behavior of the circuit, which can then be applied to the cube of capacitors. The complexity increases when dealing with capacitors of varying values, making uniformity in values advantageous for analysis. Ultimately, the goal is to determine the total capacitance between the diagonal corners of the capacitor cube. Understanding these foundational concepts is crucial for solving the capacitance problem effectively.
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If I have a cube made out of capacitors, that's one capacitor for everyside for a total of 12 capacitors. Each capacitor is C=4.71 pF. How would I even begin to go about finding the total capacitance?
 
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I assume you mean the total capacitance between diagonal corners.

Start with a little easier problem -- a cube of resistors. There may be a shortcut way, but write the node equations for each of the 8 vertexes, and take advantage of the fact that the resistors have equal value. After you see how that works out, do the cube of capacitors.

Problems like this get harder when the components are of different values.
 
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