Find v(z) given volume charge density

AI Thread Summary
To find v(z) for a parallel plate capacitor with a given volume charge density ρ_v = ρ_o*sin(pi*z/2*d), integration is necessary. The first integral leads to -ρ_o*2d/pi*cos(pi*z/2*d) + A = dv/dz. The second integration yields v(z) = -ρ_o*(2d/pi)^2*sin(pi*z/2*d) + Az + B. It's important to define the limits of integration to determine the constants accurately, and the discussion notes a potential omission of ε0 in the calculations. Properly addressing these points is crucial for an accurate solution.
derek l

Homework Statement


Consider the parallel plate capacitor(no figure). The capacitor plates have a separation distance d in the z-direction. The volume charge density is given by ρ_v. Find v(z).

Homework Equations


ρ_v = ρ_o*sin(pi*z/2*d)

The Attempt at a Solution


[/B]
∫(ρ_vdz) = -ρ_o*2d/pi*cos(pi*z/2*d) +A= dv/dz

∫dv/dz = -ρ_o*(2d/pi)^2*sin(pi*z/2*d) +Az + B = v(z)
 
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You need to consider definite integrals so that the integration constants can be defined. What are your limits of integration? Also, it looks like you are missing an ε0 somewhere.
 
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