Find values for z for which the function f grows

Click For Summary

Homework Help Overview

The original poster attempts to find values for x for which the function f, defined as the sum of two integrals, grows. The function involves an integral from -3 to x of t^4*e^(t^2) and another integral from x^2 to 2 of t*e^t.

Discussion Character

  • Exploratory, Assumption checking

Approaches and Questions Raised

  • Participants discuss the method of determining when a function is increasing, with one suggesting the need to find the derivative of the function and identify where it is greater than zero. There is also a mention of caution regarding the derivative of the second integral with respect to x.

Discussion Status

Some participants have provided guidance on the approach to take, particularly regarding the derivative and conditions for growth. There is an acknowledgment of the need for careful calculation, but no consensus has been reached on the specific values of x.

Contextual Notes

There is a warning about not showing an attempt, indicating that participants are expected to engage with the problem actively. The discussion reflects on the complexities involved in differentiating the integrals.

AndrejN96
Messages
26
Reaction score
0
Member warned about not showing an attempt.
1. Homework Statement


As the title says, I am supposed to find values for x for which the function given below grows.

f(x)=(integral from -3 to x of t^4*e^(t^2)dt)+(integral from x^2 to 2 of t*e^tdt)

Homework Equations

The Attempt at a Solution



I tried solving using substitution or partial integration but I am stuck.
 
Last edited by a moderator:
Physics news on Phys.org
Is this what you have:

##f(x) = \int_{-3}^{x} t^4 e^{t^2} dt + \int_{x^2}^2 te^tdt##

How would you normally work out when a function is increasing?
 
PeroK said:
Is this what you have:

##f(x) = \int_{-3}^{x} t^4 e^{t^2} dt + \int_{x^2}^2 te^tdt##

How would you normally work out when a function is increasing?
I would find the derivative of the function and find for which values of x the value is >0. Totally overlooked it. Thank you.
 
Just to say, i think you might need to put just a tiny bit more caution when calculating the derivative of \int_{x^2}^{2}te^tdt wrt x.
 

Similar threads

Replies
8
Views
2K
Replies
3
Views
2K
Replies
2
Views
2K
  • · Replies 3 ·
Replies
3
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 18 ·
Replies
18
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
Replies
6
Views
3K
  • · Replies 3 ·
Replies
3
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K