Find Vector Perpendicular to Plane

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Discussion Overview

The discussion revolves around finding a vector that is perpendicular to a plane defined by three points in three-dimensional space: P (1, 2, 3), Q (2, 3, 1), and R (3, 1, 2). The focus is on the mathematical approach to determine this perpendicular vector, specifically through the use of vector products.

Discussion Character

  • Mathematical reasoning

Main Points Raised

  • One participant suggests using the vector product of two vectors derived from the points P, Q, and R to find a perpendicular vector.
  • Another participant expresses confusion regarding the concept of the vector product and its calculation.
  • Further clarification is attempted by providing the vectors $\vec{PQ}$ and $\vec{PR}$, along with the determinant setup for the vector product.

Areas of Agreement / Disagreement

There is no consensus on understanding the vector product, as some participants express confusion about the concept and its calculation.

Contextual Notes

Some participants may lack familiarity with vector operations, particularly the vector product, which could affect their understanding of the discussion.

brinlin
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Find a vector that is perpendicular to the plane passing through the points P (1, 2, 3), Q (2, 3, 1), and R (3, 1, 2).
 
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vector product yields a vector perpendicular to two vectors ...

$\vec{PQ} \times \vec{PR}$
 
I'm sorry I don't really understand.
 
brinlin said:
I'm sorry I don't really understand.

you don't understand, or you don't know what a vector product is and how to calculate it?

$\vec{PQ} = (1,1,-2)$
$\vec{PR} = (2,-1,-1)$

$ \vec{PQ} \times \vec{PR} = \begin{vmatrix} \hat{i} & \hat{j} & \hat{k} \\ 1& 1 & -2 \\ 2 &-1 &-1 \\ \end{vmatrix} $
 

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