Find Wavelength of Light Through Slits

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To find the wavelength of light in a double slit experiment, the formula used is y = λL/d, where y is the distance of the first maxima from the center, L is the distance to the screen, and d is the slit separation. The user initially calculated the wavelength incorrectly by misidentifying the variables. The correct values are y = 0.03 m (half the distance between maxima), L = 2 m, and d = 9.12 x 10^-3 cm. After clarification, the user confirmed understanding of the formula and variables. This highlights the importance of correctly identifying parameters in physics calculations.
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Almost done guys :)

If the first order bright lines formed by two slits at a distance of 2 meters are 3 cm apart, find the wavelength of the light if the slit separation is 9.12x10^-3 cm.

So, to find the wavelength, this is what I did.

wavelength = 9.12 * 10^-5m * (2m/(3*10^-2m)) = .00608m.

i'm not understanding what i am doing wrong. any input would be helpful. Thanks!
 
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You need to understand the formula for the double slit diffraction pattern. The distance of the first maxima (from the central maxima) is given by:
y = \frac{\lambda L}{d}
 
Doc Al said:
y = \frac{\lambda L}{d}


right, so y=9.12*10^-5m, d = 2m and L = 3*10^-2m.
 
daisyi said:
right, so y=9.12*10^-5m, d = 2m and L = 3*10^-2m.
Nope:
L is the distance to the screen
d is the distance between the slits
y is the distance of the first maxima to the center (this is half of the distance between those maxima).
 
thanks, i got it :)
 
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