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Homework Help: Find x in Tan trig problem

  1. Jun 13, 2010 #1
    1. The problem statement, all variables and given/known data

    tan((π(x))/2) = √(3)/2

    2. Relevant equations

    3. The attempt at a solution
    tan(x) = √(3)/2
    x= π/6 + πn, since Tan has a period of π
    This is where I'm stuck
  2. jcsd
  3. Jun 13, 2010 #2


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    Gold Member

    Re: Trigonometry

    tan(pi*x/2) = sqrt(3)/2
    pi*x/2 = arctan(sqrt(3)/2)

    x = (2*arctan(sqrt(3)/2))/pi

    What is required of you? Find x?
  4. Jun 13, 2010 #3
    Re: Trigonometry

    Yea Find x
  5. Jun 13, 2010 #4


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    Gold Member

    Re: Trigonometry

    Oh ok no problem
    Last edited: Aug 21, 2010
  6. Jun 13, 2010 #5


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    Homework Helper

    Re: Trigonometry

    I also found an x in your name! Funny that.

    Well since for [tex]tan(x)=\frac{\sqrt{3}}{2}[/tex]

    [tex]x=\frac{\pi}{6}+\pi n[/tex]

    Then if we instead have [tex]tan\left(\frac{\pi x}{2}\right)=\frac{\sqrt{3}}{2}[/tex]

    We end up with [tex]\frac{\pi x}{2}=\frac{\pi}{6}+\pi n[/tex]

    and now solve for x. Simple, no? :smile:

    EDIT: [tex]tan(\pi/6)=1/\sqrt{3}[/tex], not [tex]\sqrt{3}/2[/tex]. Since it's not a nice number, it's best to leave it as [tex]arctan(\sqrt{3}/2)[/tex]
    Last edited: Jun 13, 2010
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