Finding a parametric form and calculating line integrals.

YogiBear
Messages
7
Reaction score
0

Homework Statement


Let C be the straight line from the point r =^i to the point r = 2j - k
Find a parametric form for C. And calculate the line integrals ∫cV*dr and ∫c*v x dr where v = xi-yk. and is a vector field

Homework Equations

The Attempt at a Solution


For parametric form (1-t)i + (2*t)j - t k
For second part i need help
 
Physics news on Phys.org
Hello Yogi, welcome (belated) to PF :smile: !

So you have ##\vec v = x \hat \imath - y \hat k## and need ##\vec {dr}##, right ?

The path is from (1,0,0) to (0,2,1) , starts at t = 0 and ends at t = 1 in the parametric form. What would be ##\vec {dr}## ?

When I think over what to do for this one, I make a little drawing and check
 
  • Like
Likes YogiBear
Thank you solved, it. <3
 
Prove $$\int\limits_0^{\sqrt2/4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx = \frac{\pi^2}{8}.$$ Let $$I = \int\limits_0^{\sqrt 2 / 4}\frac{1}{\sqrt{x-x^2}}\arcsin\sqrt{\frac{(x-1)\left(x-1+x\sqrt{9-16x}\right)}{1-2x}} \, \mathrm dx. \tag{1}$$ The representation integral of ##\arcsin## is $$\arcsin u = \int\limits_{0}^{1} \frac{\mathrm dt}{\sqrt{1-t^2}}, \qquad 0 \leqslant u \leqslant 1.$$ Plugging identity above into ##(1)## with ##u...

Similar threads

Back
Top