Finding Acceleration in Two-Dimensional Kinematics

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The discussion revolves around calculating the acceleration of a flying saucer with constant acceleration, given its positions and velocities without a specified time. Participants suggest using the chain rule to relate velocity and position for acceleration calculations. Clarification is provided that the position vector only indicates location, while the direction of the trajectory indicates velocity direction. There is confusion about how to interpret the provided information in the form of a diagram versus a graph. Ultimately, it is recommended to focus on using the velocity values directly for calculations rather than relying on graphical methods.
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Homework Statement


a flying saucer manueverign with a constant acceleration is observed with the positions and velocities shown below. what is the saucer's acceleration?

Homework Equations


a = \Deltav / t

The Attempt at a Solution


so a time is not given.. is there another way to find acceleration?
** actually if someone knows a site that gives a clear and concise tutorial on two-dimensional kinematics that would be great :). I know there is one attached to this site.. but i do better with actual examples and more visual.
 

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indietro said:
a flying saucer manueverign with a constant acceleration is observed with the positions and velocities shown below. what is the saucer's acceleration?

so a time is not given.. is there another way to find acceleration?

Hi indietro! :smile:

(I can't see the picture yet, but …)

The standard trick for finding dv/dt from v and s without involving t is to use the chain rule …

dv/dt = dv/dx dx/dt = v dv/dx :wink:
 
oo ok for the picture it is a x-y graph that shows a point at (0.0) with a vertical vector (200\hat{j} m/s) and a second point at (2000, 1000) with a south-east vector (200\hat{i} - 100\hat{j} m/s)

for the chain rule: is the v the final velocity?
 
v = dx/dt
 
so i have a question: for an x-y graph showing the trajectory, what does \vec{r} (starts at origin and goes to a point on the trajectory) tell me? the velocity at that point? or does it only tell me the direction of velocity at that point?
 
sorry but I am really confused as how to relate an xy-graph, a vx graph, a vy graph and acceleration. Like what does each tell me, how can i find position after a certain time, how can i find acceleration?
 
Hi indietro! :smile:

(just got up :zzz: …)
indietro said:
so i have a question: for an x-y graph showing the trajectory, what does \vec{r} (starts at origin and goes to a point on the trajectory) tell me? the velocity at that point? or does it only tell me the direction of velocity at that point?

r only tells you the position, and the direction of the tangent of the trajectory tells you the direction of the velocity.
indietro said:
sorry but I am really confused as how to relate an xy-graph, a vx graph, a vy graph and acceleration. Like what does each tell me, how can i find position after a certain time, how can i find acceleration?

Why are you using a graph? Does the question tell you to?

If it doesn't, then forget graphs, and just use equations. :smile:
 
yes the question gives me all the information in the form of an vx graph and vy graph ...:(
 
indietro said:
yes the question gives me all the information in the form of an vx graph and vy graph ...:(

hmm … I still can't see your picture.

I'll have to wait until I can see it.

(I've reported it, so hopefully it'll come up soon :redface:)
 
  • #10
oooh, I see it now! :-p

ok, that isn't a graph (a graph would be a continuous curve) …

it's just a diagram, defining the two velocities in a picture instead of in words.

So you don't have to use a "graph method" …

just write the velocities as 200j and 200i - 100j, and carry on from there. :smile:
 
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