Finding an Equation through Integrals

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The discussion focuses on deriving the position function x(t) from the given acceleration equation ax = bt, where b is a positive constant. The velocity function is determined by integrating the acceleration, resulting in v(t) = 0.5 * b * t^2 + C, with C representing the initial velocity v0. The position function is then found by integrating the velocity function, which requires including another constant. The initial conditions at t = 0 help determine these constants, leading to the final expressions for both velocity and position. The key takeaway is the importance of integrating correctly and applying initial conditions to find the constants.
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Position Function from Constant Acceleration Equation

Homework Statement



The acceleration of a certain rocket is given by ax = bt, where b is a positive constant.

(a) Find the position function x(t) if x = x0 and v0 at t = 0. (Use x_0 for x0, v_0 for v0, b, and t as necessary.)
x(t) =


Homework Equations



(Hint given): The velocity function is the time integral of the acceleration function. The position function is the time integral of the velocity function. The two integration constants can be determined by applying the given initial conditions when the time is equal to zero.

\Deltas = vi(\Delta) + (1/2)a(\Delta)2


The Attempt at a Solution



ax = bt

so a = bt

v = int (a dt) = b * int (t dt) = b (.5t2)

x = b/2 int (t2) dt

Is my thinking in the right spot? I don't know if I'm not integrating correctly or if I need to plug the integrations into an equation...?
 
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You have to include a constant C when integrating. So v=0.5*b*t2+C.

If the initial velocity is v0, C=v0.

Now integrate v(t), do not forget the integration constant again.

ehild
 
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