Finding angle X when given an inequation and a weird equation

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The discussion revolves around solving the equation sin(x) + sin(2x) + sin(3x) = 0, with a focus on finding angle X within the range π/2 < x < π. Participants suggest using the sum-to-product formulas and the double-angle formula to simplify the equation. It is recommended to expand sin(2x) and express sin(3x) as sin(2x + x) to facilitate factoring. Additionally, the identity sin²(x) + cos²(x) = 1 is highlighted as a useful tool in the factoring process. The conversation emphasizes the need for a systematic approach to tackle the problem effectively.
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Homework Statement



sin (x) + sin (2x) + sin (3x) = 0
http://www4b.wolframalpha.com/Calculate/MSP/MSP531196eg6ff0edb8i9400000gb08c7ag3hfbfeh?MSPStoreType=image/gif&s=8

Sorry for not following the recommended layout, it's just that this question boggles me and I don't know any relevant formulas or where to start.

I know the http://www28.wolframalpha.com/input/?i=sin+x+++sin+2x+++sin+3x+=+0,+pi/2+<+x+<+pi"but I don't know how to get to it.

Thanks in advance to whoever tries to help
 
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Do you know a formula for sinP+sinQ? (or the sum to product formula for sin?)
 
Use the double-angle formula to expand the sin(2x) and sin(3x) - notice that sin(3x)=sin(2x+x) , then collect like terms and factor as much as possible while using sin^2(x)+cos^2(x)=1 to aid you in the factoring process.
 
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