Finding Angular Frequency of Small Oscillations about an Equilibrium

AI Thread Summary
The discussion focuses on finding the angular frequency of small oscillations around the equilibrium point of a system described by a Lagrangian equation. The initial approach suggests using potential energy to derive angular frequency, but this is deemed incorrect due to unit inconsistencies between the variables involved. Instead, participants are encouraged to convert the Lagrangian equation into the standard form of the simple harmonic motion differential equation. They emphasize the importance of considering small-angle approximations, where higher-order terms like theta cubed can be neglected. Ultimately, the correct method involves deriving the angular frequency from the Lagrangian formulation rather than relying solely on potential energy.
Oijl
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Homework Statement


Consider a system of one generalized coordinate theta, having the following Lagrangian equation of motion:

r and b are constants
m is mass

(1/3)mb^{2}\ddot{\theta} = r(r+b)\theta + r^{2}\theta^{3} + gr\theta

And this potential energy (if it matters):

U = mg(r+b) - mgr\theta^{2}


There is an equilibrium point where theta is equal to zero.

Find the angular frequency of small oscillations about \theta = 0.


Homework Equations





The Attempt at a Solution



Using the potential energy, can't I just say

U = (1/2)k\theta^{2}
where
k = 2mgr
so that I can write
\omega = (k/m)^(1/2)
\omega = (2gr)^(1/2)
and call that the angular frequency?

But the problem asks me to do it the Lagrangian way.

So
\omega = (2\pi)/\tau

How can I find tau?
 
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Oijl said:
Using the potential energy, can't I just say

U = (1/2)k\theta^{2}
where
k = 2mgr
so that I can write
\omega = (k/m)^(1/2)
\omega = (2gr)^(1/2)
and call that the angular frequency?

Clever, but it's not right. You can see this by comparing the units of U=(1/2)kx^2 with those of U = (1/2)k\theta^{2}: both U's have the same unit, both x doesn't have the same unit as theta, so the two k's must have different units. That means the equation omega=(k/m)^1/2 is not correct.

To start, do you know the characteristic differential equation for simple harmonic motion? Try to get the Lagrangian equation of motion into that form, remembering that theta^3 is much smaller than theta for small values of theta.
 
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