Finding average power for an object being vertically lifted

  • Thread starter Thread starter emilykorth
  • Start date Start date
  • Tags Tags
    Average Power
Join the discussion
Ask a follow-up here, or get your own question answered by working scientists, mathematicians and engineers — people, not an autocomplete.
Real named experts · corrections over time · the nuance an AI answer skips
2 replies · 6K views
emilykorth
Messages
13
Reaction score
0

Homework Statement



If a ski lift raises 100 passengers averaging 668 N in weight to a height of 175 m in 60 s, at constant speed, what average power is required of the force making the lift?

Homework Equations


P_instantaneous=Fv
P=W/t
W=Fd

The Attempt at a Solution


I tried to solve this by first using W=fd to find W...so 668/175=3.817
I then used P=W/t so 3.817/60
however this answer was wrong...what am I doing wrong?
 
Physics news on Phys.org
emilykorth said:

Homework Statement



If a ski lift raises 100 passengers averaging 668 N in weight to a height of 175 m in 60 s, at constant speed, what average power is required of the force making the lift?

Homework Equations


P_instantaneous=Fv
P=W/t
W=Fd

The Attempt at a Solution


I tried to solve this by first using W=fd to find W...so 668/175=3.817
I then used P=W/t so 3.817/60
however this answer was wrong...what am I doing wrong?
668 Newtons is the average weight of one of the passengers.

Secondly, why are you dividing by the distance?
 
wow I was making a really stupid mistake. Thanks for the help, I figured it out