Finding Centre of Mass for a Uniform Semicircular Lamina

brandon26
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Where is the centre of mass of a semicircular lamina which is uniform? I know it is somewhere along the line of symestry, but where excactly?:confused:
 
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It only takes a few moments to work it out.
com = 4r/3pi:smile:
 
Can you be of more help please?
 
Of course. Drag your mouse over the answer in my last post.
 
Surely, if you have a question like that, you know the basic formulas.

The y-coordinate of the centroid of a region (center of mass assuming uniform density) is \frac{\int y dA}{\int dA}.
\int dA is, of course, the area of the region.


Once, when I was teaching this, a student became fascinated by the word "lamina" (had never seen it before, apparently). As the last question on the final exam, I asked "What is 'lamina' spelled backwards?"

Another student became furious with me because "That question doesn't make any sense!"
 
Fermat said:
Of course. Drag your mouse over the answer in my last post.
Oh sorry. Haha. I didnt realize there was invisible ink on the paper.
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...

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