Finding Centroid of Triangle in First Quadrant

  • Thread starter Thread starter magma_saber
  • Start date Start date
  • Tags Tags
    Centroid
magma_saber
Messages
73
Reaction score
0

Homework Statement


Find the centroid of the triangular region in the first quadrant bounded by the line 4x+y=4, the x-axis, and the y-axis.


Homework Equations


\int\int\deltadA
xbar = My/M
ybar = Mx/M

The Attempt at a Solution


Is the boundary for the dy from 0 to 4, and dx from 0 to 4-4x?
 
Physics news on Phys.org
No, your limits for x can't contain x. They can only depend on y.
 
so its y-4/4?
also are my limits for dy correct?
 
No, that's not quite correct either. (I assume you mean (y-4)/4, not y-1.) You should always plug in a few values to do a sanity check. In this case, when y=0, you'd get a negative answer.

Your limits for y are fine. (But I'll note I'm saying this under the assumption that you set things up correctly.)

Did you draw a sketch of the region of integration?
 
the region would be the triangle from y=4 to y=0 and x=0 and x=1 right?
and is the limit 4-4x?
 
There are two things I don't understand about this problem. First, when finding the nth root of a number, there should in theory be n solutions. However, the formula produces n+1 roots. Here is how. The first root is simply ##\left(r\right)^{\left(\frac{1}{n}\right)}##. Then you multiply this first root by n additional expressions given by the formula, as you go through k=0,1,...n-1. So you end up with n+1 roots, which cannot be correct. Let me illustrate what I mean. For this...
Back
Top