Finding constant in Probability density function.

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Homework Help Overview

The discussion revolves around finding the constant \( k \) in a probability density function (pdf) for a continuous random variable \( X \). The pdf is defined piecewise, with a specific form for the interval \( 0 \leq x \leq 1 \) and zero otherwise.

Discussion Character

  • Conceptual clarification, Mathematical reasoning

Approaches and Questions Raised

  • The original poster attempts to solve for \( k \) by integrating the pdf over the specified interval and setting the result equal to 1, which is a common requirement for probability density functions. Some participants question the meaning of normalizing the pdf to 1 and clarify the process involved in this normalization.

Discussion Status

The discussion is active, with participants confirming the approach taken by the original poster and seeking clarification on terminology related to normalization. There appears to be a shared understanding of the need to ensure the integral of the pdf equals 1, though some participants are still exploring the implications of this requirement.

Contextual Notes

There are repeated inquiries about the normalization process, indicating some uncertainty about the terminology and its application in this context. The discussion reflects a focus on understanding the foundational concepts behind probability density functions.

sid9221
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A continuous random variable X has pdf:

f_X(x)=\left \{ k(x+3), 0\leq x\leq 1\right \}

0 otherwise.

Find k.

I solved the integral (from 0..1) and solved for the result equal to 1.

Hence I got k=2/7.

Is this the right way to proceed as the question continues and I want to check if I'm starting correctly
 
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yep, you just want to normalise to 1
 
What do you mean normalize to 1 ?

It was 7/2k=1
So k=2/7

?
 
sid9221 said:
What do you mean normalize to 1 ?

It was 7/2k=1
So k=2/7

?

Normalizing means making \int_0^1 f_X(x) \, dx = 1.

RGV
 

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