Finding Current in a Circuit with 3 Switches

AI Thread Summary
To find the current at point 'a' in a circuit with three switches (S1, S2, S3), one must analyze all possible switch combinations, resulting in eight configurations. Each switch can either be open or closed, affecting the circuit's overall resistance and current flow. The fundamental equation V = iR is used to calculate current, where V is the voltage (170 V) and R is the total resistance based on the switch settings. To simplify the analysis, the circuit can be redrawn for each configuration, replacing closed switches with wires and removing components in series with open switches. Understanding the impact of open and closed switches on circuit resistance is crucial for solving the problem.
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Homework Statement



A circuit containing three switches, labeled S1, S2, and S3.
Find the current at a for all possible combinations of switch settings.
Put = 170 V, R1 = 30.0 , and R2 = 10.0 .
Assume that the battery has no resistance.

(S1, S2, and S3 all open)
(S1 closed, S2 and S3 open)
(S2 closed, S1 and S3 open)
(S3 closed, S1 and S2 open)
(S1 open, S2 and S3 closed)
(S2 open, S1 and S3 closed)
(S3 open, S1 and S2 closed)
(S1, S2, and S3 all closed)

Figure Shown here: http://www.webassign.net/hrw/28_37.gif"

Homework Equations



V=iR

The Attempt at a Solution


I'm confused on what it means when a circuit is open or closed, so I don't know how that affects the current.

Also, I don't know how to account for the 2 resistances.

Please help! :)
 
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The switches are open or closed. You just have to draw 8 versions of the circuit, with the closed switches replaced by a wire, and the open switches, and everything that's in series with them removed from the circuit.

You could draw a tree with the original cicuit at the root, and then 2 circuits as branches, one of them with S3 closed and one of them with S3 open. Simplify those circuits by replacing series and parallel resistances. Then split both branches in a branch with S2 closed and s2 open. replace series and parallel resistances again, etc.
 
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