sgtserious
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I am having a really hard time with dynamics of rigid bodies, but i think doing this problem will clear up some confusion i have.
A massless rope hanging over a frictionless pulley of mass M supports two monkeys (one of mass M, the other of mass 2M). The system is released at rest at t = 0. During the following 2 sec, monkey B travels down 15 ft of rope to obtain a massless peanut at P. Monkey A holds tightly to the rope during these two sec. Find the displacement of A during the time interval. Treat the pulley as a uniform cylinder of radius R.
Relevant picture: diagram
As mentioned in the topic title, the problem has to do with impulse momentum:
∫ƩFy = m(y'f - y'i) [for monkey A]
∫ƩFy = m(y'f - y'i) [for monkey B]
∫ƩM = (I^{c}_{zz}w)_{f} -(I^{c}_{zz}w)_{i} [for the pulley of mass M]
This is what I tried to do
(all initial velocities and angular velocities are zero)
For monkey A:
∫^{2}_{0}(T_{1} - Mg) dt = M*y'_{A}_{f}
-> T_{1}*t - Mgt = M*y'_{A}_{f}
-> 2T_{1} -2Mg = M*y'_{A}_{f}
For monkey B:
∫^{2}_{0}(T_{2} - 2Mg) dt = 2M*y'_{B}_{f}
-> T_{2}*t - 2Mgt = 2M*y'_{B}_{f}
-> 2T_{2} - 4Mg = 2M*y'_{B}_{f}
For the pulley:
∫^{2}_{0}(MgR - 2MgR) dt = (I^{c}_{zz}w)_{f}
-> -2MgR = (1/2)MR^{2}w_{f}
From the conclusion of all three sets of equations, I have 5 unknowns, with only three equations
I figure from here I need to some kinematics:
By circular motion, the y'_{A} = R*w_{f}, which helps eliminate one unknown
In addition, there is the length of rope connecting the three bodies, but considering the pulley has mass, I am not sure how to relate the velocities of point A and point B
I believe I get stuck a lot on the kinematic constraints, and here I am not sure how to solve the system of equations I developed
Any help is greatly appreciated
Homework Statement
A massless rope hanging over a frictionless pulley of mass M supports two monkeys (one of mass M, the other of mass 2M). The system is released at rest at t = 0. During the following 2 sec, monkey B travels down 15 ft of rope to obtain a massless peanut at P. Monkey A holds tightly to the rope during these two sec. Find the displacement of A during the time interval. Treat the pulley as a uniform cylinder of radius R.
Relevant picture: diagram
Homework Equations
As mentioned in the topic title, the problem has to do with impulse momentum:
∫ƩFy = m(y'f - y'i) [for monkey A]
∫ƩFy = m(y'f - y'i) [for monkey B]
∫ƩM = (I^{c}_{zz}w)_{f} -(I^{c}_{zz}w)_{i} [for the pulley of mass M]
The Attempt at a Solution
This is what I tried to do
(all initial velocities and angular velocities are zero)
For monkey A:
∫^{2}_{0}(T_{1} - Mg) dt = M*y'_{A}_{f}
-> T_{1}*t - Mgt = M*y'_{A}_{f}
-> 2T_{1} -2Mg = M*y'_{A}_{f}
For monkey B:
∫^{2}_{0}(T_{2} - 2Mg) dt = 2M*y'_{B}_{f}
-> T_{2}*t - 2Mgt = 2M*y'_{B}_{f}
-> 2T_{2} - 4Mg = 2M*y'_{B}_{f}
For the pulley:
∫^{2}_{0}(MgR - 2MgR) dt = (I^{c}_{zz}w)_{f}
-> -2MgR = (1/2)MR^{2}w_{f}
From the conclusion of all three sets of equations, I have 5 unknowns, with only three equations
I figure from here I need to some kinematics:
By circular motion, the y'_{A} = R*w_{f}, which helps eliminate one unknown
In addition, there is the length of rope connecting the three bodies, but considering the pulley has mass, I am not sure how to relate the velocities of point A and point B
I believe I get stuck a lot on the kinematic constraints, and here I am not sure how to solve the system of equations I developed
Any help is greatly appreciated