# Finding distance from force

1. Jan 22, 2010

### magnifik

1. The problem statement, all variables and given/known data
A dockworker applies a constant horizontal force of 72.0N to a block of ice on a smooth horizontal floor. The frictional force is negligible. The block starts from rest and moves a distance 10.0m in a time 4.50s. If the worker stops pushing at the end of 4.50 , how far does the block move in the next 5.70s?

2. Relevant equations
v = at
x = x0 + v0t + 1/2at^2

3. The attempt at a solution
I realized this is only a kinematics problem, but I keep getting the wrong answer. I got 32.1m, but the answer is 25.3m. I did v=at, plugging in 0.987654321*5.70 then multiplied this answer by 5.70. What am I doing wrong??

2. Jan 22, 2010

### ideasrule

3. Jan 22, 2010

### magnifik

Weird. I copied & pasted the exact question from the website. Stupid MasteringPhysics -____-

4. Jan 22, 2010

### rl.bhat

I did v=at, plugging in 0.987654321*5.70
You have to find the velocity at the end of 4.5s.

5. Jan 22, 2010

### ideasrule

Oops, I somehow missed that too. Sorry magnifik!