Finding Distance with Varying Force: A Homework Problem

  • Thread starter Thread starter Xamfy19
  • Start date Start date
  • Tags Tags
    Force
AI Thread Summary
The discussion revolves around a physics homework problem involving an object subjected to a time-varying force described by F(t) = k*e^(-c*t). The object has a mass of 1.0 kg, an initial velocity of 2.0 m/s, and is located at the origin at time t=0. To find the object's position after 20 seconds, the user is advised to apply Newton's second law, F = m(dv/dt), to derive velocity as a function of time. The next step involves integrating the velocity function to determine the displacement over the specified time interval. This approach clarifies how to handle varying forces in calculating distance.
Xamfy19
Messages
60
Reaction score
0

Homework Statement


An object of mass m=1.0kg experiences a force of the following mathematical form,

F(t)=k*e^(-c*t) i

where k=6.0N and c=0.10 (1/s) and i indicates the unit vector in the x-direction.At time t=0, the object has a velocity of v=2.0 m/s and is at the origin. Where is this object after 20 seconds?

Homework Equations


F=ma.. maybe..

The Attempt at a Solution


I used the force equation and F=ma to get the acceleration and was going to use the x=(vo)t +(1/2a)t^2 equation, but then I realized that doesn't make sense... I'm kind of confused though... How do you find the distance if the force varies? Thanks in advance.
 
Physics news on Phys.org
Once you've found the acceleration, as you say, use the most general form of the equations between acceleration, velocity and displacement to find the displacement for this case.

Dorothy
 
You should use the Newton's second law in this form

F = m\frac{dv}{dt}

Then you find v as a function of time t.

Remember that dx = vdt.

Calculate \int_0^{20}dx to find the answer.
 
Thread 'Variable mass system : water sprayed into a moving container'
Starting with the mass considerations #m(t)# is mass of water #M_{c}# mass of container and #M(t)# mass of total system $$M(t) = M_{C} + m(t)$$ $$\Rightarrow \frac{dM(t)}{dt} = \frac{dm(t)}{dt}$$ $$P_i = Mv + u \, dm$$ $$P_f = (M + dm)(v + dv)$$ $$\Delta P = M \, dv + (v - u) \, dm$$ $$F = \frac{dP}{dt} = M \frac{dv}{dt} + (v - u) \frac{dm}{dt}$$ $$F = u \frac{dm}{dt} = \rho A u^2$$ from conservation of momentum , the cannon recoils with the same force which it applies. $$\quad \frac{dm}{dt}...
Back
Top