Finding Electric field magnitude of a wire

AI Thread Summary
To find the electric field magnitude produced by a uniformly charged plastic wire, the charge density is given as +175 nC/m along an 8.50 cm length. The electric field needs to be calculated at a point 6.00 cm above the wire's midpoint. The integration limits depend on the variable chosen for integration, either x or r, and should not be set from 0.00 cm to 6.00 cm. The relationship between r and x must be established using the Pythagorean theorem, as both are variables in the calculation. Properly setting up the integration will yield the electric field's magnitude and direction.
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Homework Statement


A plastic wire 8.50cm long carries a charge density of +175 nC/m distributed uniformly along its length. it is lying on a horizontal tabletop

A) find the magnitude and direction of the electric field this wire produces at a point 6.00 cm directly above its midpoint


Homework Equations



dq= lamdadx dE= kdq/r^2

The Attempt at a Solution



The part where i am stuck is what should the limits of integration be? 0.00 cm to 6.00 cm?

and what should r^2 be? 6.00 cm?
 
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Note that both r and x are variables; neither are constants. Express one of them in terms of the other before performing the integration. Use pythagoras theorem here. As for limits of integration, it depends on what you choose to vary, either x or r.
 
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