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## Homework Statement

A battery has a current of 3.0A flow through it. It has an internal resistance of 0.039Ω and the circuit has a load of 45Ω.

a) What is the emf?

b) What is the voltage that flows?

## Homework Equations

V = ε - IR

## The Attempt at a Solution

ε = V + IR

ε = (45Ω)(3A) + (3A)(0.039Ω)

ε = 135V + 0.117V

a) 135.117V

b) 135V

I'm new to emf. Does this look correct? If not, can you explain where I went awry?